[LRUG] Sorting a hash by value

Sam Livingston-Gray geeksam at gmail.com
Tue Jun 17 07:15:56 PDT 2014


Taking a cue from @JEG2, you could reverse it:

catalogue.select {...}.map(&:reverse).sort.map(&:reverse)

...but (as already mentioned) #sort_by is much easier to read:

catalogue.select {...}.sort_by(&:last)

--
(Sent from phone. Please excuse: brevity, top posting, hilarious autocorrections.)

> On Jun 17, 2014, at 3:46 AM, Stephen Nelson-Smith <sanelson at gmail.com> wrote:
> 
> I have a hash that looks like this:
> 
> {"ami-c3c73c7f"=>"tn-example 1980-09-12T17:53:25Z",
>  "ami-600925fe"=>"sns-example 1983-01-05T16:21:08Z",
>  "ami-131f1007"=>"dk-example 2005-01-27T23:03:01Z",
>  "ami-98d4ddef"=>"tn-example 2002-10-27T11:52:26Z",
>  "ami-fe6af742"=>"sns-example 1998-11-22T09:54:51Z",
>  "ami-09966e45"=>"dk-example 1993-01-09T13:23:45Z",
>  "ami-44e6ee6a"=>"tn-example 2013-12-23T20:52:28Z",
>  "ami-cbf7f1a9"=>"sns-example 1979-09-09T07:15:47Z",
>  "ami-fcd2e7ac"=>"dk-example 2007-09-02T18:34:05Z"}
> 
> I want to filter this hash by value and return them in sorted date order.  The implementation I have just seems ugly:
> 
> catalogue.select {|id, name| name.match /sns-example/ }.sort { |id, name| name[1] <=> id[1] }
> => [["ami-a65e21cc", "sns-example 2011-10-03T11:15:49Z"],
>  ["ami-9a401c41", "sns-example 1983-09-22T15:26:00Z"],
>  ["ami-9f9ae4d8", "sns-example 1971-03-06T03:58:52Z"]]
> 
> 
> I don't like the way sort takes my hash and makes it into an array of tuples... and I'd really like it to return an array of single key/value hashes... 
> 
> Also, is there a more elegant way to perform the filter/search?
> 
> S.
> 
> -- 
> Stephen Nelson-Smith
> Technical Director
> Atalanta Systems Ltd
> www.atalanta-systems.com
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